Chapter 5: Exponential and Logarithmic Functions
Logarithms as inverse exponents, log rules, exponential models, and classic science/finance applications.
Problems Covered
5.1 What a Logarithm Means
A logarithm asks for an exponent. The expression \log_b(a) means: the exponent on base b that produces a.
To translate a logarithm, make the base the base of an exponential equation.
Worked Example 5.1.1 — Logarithm Translation
Rewrite \log_2(32)=5 in exponential form.
- Identify the base, output, and exponent.b=2,\quad a=32,\quad c=5
- Use the translation rule.\log_b(a)=c \rightarrow b^c=a
- Write the exponential statement.2^5=32
Worked Example 5.1.2 — Exponential Translation
Rewrite 3^4=81 in logarithmic form.
- Identify the base, exponent, and result.b=3,\quad c=4,\quad a=81
- Use the inverse translation.b^c=a \rightarrow \log_b(a)=c
- Write the logarithmic statement.\log_3(81)=4
5.2 Logarithm Rules
Log rules come from exponent rules. Multiplication inside a log becomes addition outside, division becomes subtraction, and powers become coefficients.
\log_b(M/N)=\log_b(M)-\log_b(N)
\log_b(M^p)=p\log_b(M)
To condense logs, move coefficients to exponents first, then combine addition as multiplication.
Worked Example 5.2.1 — Condense the Log
Condense 2\log(x)+\log(3).
- Move the coefficient into the exponent.2\log(x)=\log(x^2)
- Use the product rule.\log(x^2)+\log(3)=\log(3x^2)
5.3 Change of Base
Change of base rewrites a logarithm so it can be evaluated with a common calculator key.
For change of base, put the log of the argument over the log of the base.
Worked Example 5.3.1 — Change of Base
Evaluate \log_5(80).
- Place the argument in the numerator.\log(80)
- Place the base in the denominator.\frac{\log(80)}{\log(5)}
- Evaluate the quotient.\frac{\log(80)}{\log(5)}\approx 2.72
5.4 Classic Exponential and Logarithmic Models
Exponential models appear when a quantity changes by a constant percent or constant factor. Logarithms appear when the unknown is in the exponent or when a scale compares powers.
For continuous growth or decay, substitute into A=Pe^{rt} and solve for the missing quantity.
Worked Example 5.4.1 — Continuous Interest
An account starts with $1200 and earns 5% annual interest compounded continuously for 4 years. Find the account value.
- Use the continuous growth model.A=Pe^{rt}
- Substitute principal, rate, and time.A=1200e^{0.05(4)}
- Simplify the exponent and evaluate.A=1200e^{0.20}\approx 1465.68
The account value is about $1465.68.
5.5 Half-Life Models
A half-life model reduces a quantity by half during each equal time interval.
For half-life, divide elapsed time by the half-life to count how many halvings occur.
Worked Example 5.5.1 — Laboratory Sample
A sample starts at 80 grams and has a half-life of 6 hours. How much remains after 18 hours?
- Count the number of half-life periods.t/h = 18/6 = 3
- Apply three halvings.A=80(1/2)^3
- Evaluate the remaining amount.A=10
5.6 Richter Scale Comparisons
Logarithmic scales compare multiplicative changes. On a base-10 earthquake magnitude scale, a difference of 1 magnitude unit represents a factor of 10 in measured amplitude.
For Richter-style comparisons, subtract magnitudes and raise 10 to that difference.
Worked Example 5.6.1 — Richter Scale Comparison
Compare earthquakes of magnitude 6.4 and 4.4.
- Subtract the magnitudes.6.4-4.4=2
- Use base 10 for the comparison factor.10^2=100
The measured amplitude is 100 times as large.