Chapter 4: Quadratics and Polynomial Functions

Quadratics first: parabolas, zeros, vertex form, factoring, and the classic projectile model.

Problems Covered

4.1 Quadratics and Parabolas

A quadratic function has degree 2. Its graph is a parabola, and the vertex marks the turning point.

f(x)=ax^2+bx+c
Core Concept

For vertex form, read the turning point directly from a(x-h)^2+k.

Worked Example 4.1.1 — Thrown Ball Parabola

A ball’s height is modeled by h(t)=-(t-3)^2+25. Find the maximum height.

  • Read the vertex from vertex form.h(t)=a(t-h)^2+k
  • Identify the vertex coordinates.(h,k)=(3,25)
  • The parabola opens downward, so the vertex is a maximum.\max h(t)=25

The maximum height is 25 units.

4.2 Zeros by Factoring

Zeros are input values that make the output equal zero. Factoring turns a quadratic equation into smaller equations.

Core Concept

To solve a factored quadratic, set each factor equal to zero.

Worked Example 4.2.1 — Garden Border Zeros

Solve x^2-7x+12=0.

  • Factor the quadratic.x^2-7x+12=(x-3)(x-4)
  • Set each factor equal to zero.x-3=0 \quad \text{or} \quad x-4=0
  • Solve the two linear equations.x=3 \quad \text{or} \quad x=4

4.3 Quadratic Formula

The quadratic formula solves any quadratic equation in standard form, including equations that do not factor nicely.

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
Core Concept

When factoring is not obvious, identify a, b, and c, then substitute into the quadratic formula.

Worked Example 4.3.1 — Quadratic Formula Rescue

Solve 2x^2+3x-5=0.

  • Identify the coefficients.a=2,\quad b=3,\quad c=-5
  • Substitute into the formula.x=\frac{-3\pm\sqrt{3^2-4(2)(-5)}}{2(2)}
  • Simplify the discriminant.x=\frac{-3\pm\sqrt{49}}{4}
  • Split the two solutions.x=1 \quad \text{or} \quad x=-\frac{5}{2}

4.4 Rational Functions

Rational function pages will cover holes, vertical asymptotes, horizontal asymptotes, and sign charts. The classic problems here will include removable gaps and long-run behavior.